4x^-2y^4/8x^3(y^-2)^3

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Solution for 4x^-2y^4/8x^3(y^-2)^3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^3*((4*x^-2*y^4)/8)*(y^-2)^3 = 0

1/2*x*y^-2 = 0 // : 1/2*y^-2

x = 0

x in { 0} 

x belongs to the empty set

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